如图,梯形ABCD中,AD∥BC,对角线AC、BD交于点O,BE∥CD交CA延长线于E.求证:OC2=OA·OE.
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如图,D、E、F分别是△ABC的边AB、AC、BC的中点,连接FE并延长到点G,使GE=FE.如果△ABC的面积为20cm2,那么四边形ADEG的面积为2
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如图,直角梯形ABCD中,∠A=90°,AC⊥BD,已知| BC |
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如图:在正△ABC中,点D、E分别在边BC、CA上,使得CD=AE,AD与BE交于点P,BQ⊥AD于点Q.则| QP |
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如图,在长方形ABCD中,E、F、G分别是边AB、BC、CD的中点.已知长方形ABCD的面积是40cm2.则四边形MFNP的面积是