如图,在Rt△ABC中,∠C=90°,AC=3cm,BC=4cm,以C为圆心,CA为半径的圆交斜边于D,则BD的长为| 7 |
| 5 |
| 7 |
| 5 |
如图,等腰△ABC的顶角∠A=30°,腰长AB=2,BD为AC边上的高,根据已知条件,可求出tan15°的值为| 3 |
| 3 |
已知:如图,△ABC中,AB=AC=6,BC=4,BD⊥AC于D,则tan∠ABC的值是| 2 |
| 2 |
| 4 |
| 3 |
| 4 |
| 3 |
| ||
| 5 |
| ||
| 5 |
如图,在△ABC中,∠C=90°,sinA=| 4 |
| 5 |
| 4 |
| 3 |
| 4 |
| 3 |
| 3 |
| 3 |
| 3 |
| 2 |
| 7 |
| ||
| 2 |
| ||
| 2 |
| 3 |
| 4 |
| 7 |
| 3 |
| 3 |