试题

题目:
化简题:
(1)
2x-6
4-4x+x2
÷(x+3)×
x2+x-6
3-x

(2)-(-
a2
b
)2·(-
b2
a
)3·(
1
ab
)4·(2a3)

(3)
2+
3y
x
2-
3y
x
-
1
2
x+
y
3
1
2
x-
y
3

(4)
3-x
2x-4
÷(x+2-
5
x-2
)

(5)(x2-1)(
1
x-1
-
1
x+1
-1)

答案
解:(1)
2x-6
4-4x+x2
÷(x+3)×
x2+x-6
3-x

=
2(x-3)
(x-2)2
×
1
x+3
×
(x-2)(x+3)
3-x

=-
2
x-2


(2)-(-
a2
b
)2·(-
b2
a
)3·(
1
ab
)4·(2a3)

=
a4
b2
·
b6
a3
·
1
a4b4
·8a3
=8;

(3)
2+
3y
x
2-
3y
x
-
1
2
x+
y
3
1
2
x-
y
3

=
2x+3y
2x-3y
-
3x+2y
3x-2y

=
(2x+3y)(3x-2y)-(2x-3y)(3x+2y)
(2x-3y)(3x-2y)

=
10xy
(2x-3y)(3x-2y)


(4)
3-x
2x-4
÷(x+2-
5
x-2
)

=
3-x
2(x-2)
÷
(x+2)(x-2)-5
x-2

=
3-x
2(x-2)
×
x-2
(x+3)(x-3)

=-
1
2(x+3)


(5)(x2-1)(
1
x-1
-
1
x+1
-1)

=(x+1)(x-1)(
1
x-1
-
1
x+1
-1)
=x+1-(x-1)-(x+1)(x-1)
=3-x2
解:(1)
2x-6
4-4x+x2
÷(x+3)×
x2+x-6
3-x

=
2(x-3)
(x-2)2
×
1
x+3
×
(x-2)(x+3)
3-x

=-
2
x-2


(2)-(-
a2
b
)2·(-
b2
a
)3·(
1
ab
)4·(2a3)

=
a4
b2
·
b6
a3
·
1
a4b4
·8a3
=8;

(3)
2+
3y
x
2-
3y
x
-
1
2
x+
y
3
1
2
x-
y
3

=
2x+3y
2x-3y
-
3x+2y
3x-2y

=
(2x+3y)(3x-2y)-(2x-3y)(3x+2y)
(2x-3y)(3x-2y)

=
10xy
(2x-3y)(3x-2y)


(4)
3-x
2x-4
÷(x+2-
5
x-2
)

=
3-x
2(x-2)
÷
(x+2)(x-2)-5
x-2

=
3-x
2(x-2)
×
x-2
(x+3)(x-3)

=-
1
2(x+3)


(5)(x2-1)(
1
x-1
-
1
x+1
-1)

=(x+1)(x-1)(
1
x-1
-
1
x+1
-1)
=x+1-(x-1)-(x+1)(x-1)
=3-x2
考点梳理
分式的混合运算.
(1)先因式分解,将除法变为乘法,最后约分化简;
(2)先根据积的乘方计算,再约分化简;
(3)先根据分式的基本性质将各分式化简,再通分计算减法;
(4)先通分计算括号里面的,将除法变为乘法,最后因式分解后约分化简;
(5)根据乘法的分配律简便计算.
本题考查了分式的混合运算,通分、因式分解和约分是解答的关键.分式的混合运算,一般按常规运算顺序,但有时应先根据题目的特点,运用乘法的运算律进行灵活运算.
计算题.
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