题目：
已知α为锐角，sinα=| 2 |
| 3 |
| ||
| 3 |
| ||
| 3 |
2
| ||
| 5 |
2
| ||
| 5 |
答案
| ||
| 3 |
2
| ||
| 5 |
解：如图，∠C=90°，∠B=α，∵sinα=
| 2 |
| 3 |
∴sinα=
| AC |
| AB |
| 2 |
| 3 |
设AC=2x，AB=3x，
则BC=
| AB2-AC2 |
| 5 |
∴cosα=
| BC |
| AB |
| ||
| 3 |
tanα=
| AC |
| BC |
2
| ||
| 5 |
故答案为：
| ||
| 3 |
2
| ||
| 5 |
| 2 |
| 3 |
| ||
| 3 |
| ||
| 3 |
2
| ||
| 5 |
2
| ||
| 5 |
| ||
| 3 |
2
| ||
| 5 |
解：如图，∠C=90°，∠B=α，| 2 |
| 3 |
| AC |
| AB |
| 2 |
| 3 |
| AB2-AC2 |
| 5 |
| BC |
| AB |
| ||
| 3 |
| AC |
| BC |
2
| ||
| 5 |
| ||
| 3 |
2
| ||
| 5 |
（2003·苏州）如图，在△ABC中，∠C=90°，sinA=