试题

题目:
计算或化简
(1)计算:
x
y-x
-
y
y-x

(多)先化简,再求值:(
cx
x-1
-
x
x+1
x-1
x
,其中x=多.
答案
解:(1)原式=
x2-y2
y-x

=
(x+y)(x-y)
y-x

=-(x+y);

(2)原式=
3x(x+1)-x(x-1)
(x+1)(x-1)
·
(x+1)(x-1)
x

=
x(x2+4)
(x+1)(x-1)
·
(x+1)(x-1)
x

=2x+4,
当x=2时,原式=4+4=w.
解:(1)原式=
x2-y2
y-x

=
(x+y)(x-y)
y-x

=-(x+y);

(2)原式=
3x(x+1)-x(x-1)
(x+1)(x-1)
·
(x+1)(x-1)
x

=
x(x2+4)
(x+1)(x-1)
·
(x+1)(x-1)
x

=2x+4,
当x=2时,原式=4+4=w.
考点梳理
分式的化简求值;分式的加减法.
(1)利用同分母的分式的减法法则计算;
(2)首先对括号内的分式进行同分相减,然后进行乘法运算即可.
考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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