试题

题目：
计算：
3
x
-
6
1-x
-
x+5
x2-x
．
答案
解：原式=
3
x
+
6
x-1
-
x+5
x(x-1)

=
3(x-1)
x(x-1)
+
6x
x(x-1)
-
x+5
x(x-1)

=
3x-3+6x-x-5
x(x-1)

=
8x-8
x(x-1)

=
8
x
．
解：原式=
3
x
+
6
x-1
-
x+5
x(x-1)

=
3(x-1)
x(x-1)
+
6x
x(x-1)
-
x+5
x(x-1)

=
3x-3+6x-x-5
x(x-1)

=
8x-8
x(x-1)

=
8
x
．
考点梳理
分式的加减法．
先通分，把异分母分式加减化成同分母分式相加减，计算求解即可．
异分母分式加减运算，先通分是关键，把异分母分式化为同分母分式，然后再相加减．
计算题．
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