答案
(1)解:△ABP≌△ACP,△BPC≌△CPE,△ABE≌△ACE;
(2)选择△ABE≌△ACE进行证明.
证明:∵AD⊥BC,根据垂径定理可得BE=CE,BP=CP,
AB=AC,BE=CE,AE=AE,
∴△ABE≌△ACE.
∵AB=AC,BP=CP,
∴△BPC≌△CPE.
∵BP=CP,BE=CE,
∴△ABE≌△ACE.
(1)解:△ABP≌△ACP,△BPC≌△CPE,△ABE≌△ACE;
(2)选择△ABE≌△ACE进行证明.
证明:∵AD⊥BC,根据垂径定理可得BE=CE,BP=CP,
AB=AC,BE=CE,AE=AE,
∴△ABE≌△ACE.
∵AB=AC,BP=CP,
∴△BPC≌△CPE.
∵BP=CP,BE=CE,
∴△ABE≌△ACE.