数学
(2012·房山区一模)计算:
(
1
3
)
-1
-
8
+
|-3
2
|
-(3.14-π)
0
.
(2012·峨眉山市二模)计算:
|-
1
2
|-
4
+(-3
)
2
.
(2012·东莞模拟)计算:
(π-3
)
0
-3tan60°-
2
-1
+
27
.
(2012·东莞模拟)计算:
(2012-Π
)
0
-(
1
2
)
-1
+
12
tan30°
.
(2012·东城区二模)计算:
27
-(4-π
)
0
-6cos30°+| -2 |
.
(2012·德化县一模)计算:
(3-π
)
0
+|-2|-
8
×
2
+(-1
)
2
÷
3
-1
.
(2012·丹徒区模拟)(1)计算:2cos30°-
(
22
7
-3.14
)
0
+
12
+(
1
3
)
-1
;
(2)化简:
(
5
a-2
-a-2)÷
a-3
a
2
-4a+4
.
(2012·大丰市一模)计算与化简:
(1)tan60°+
(-2
)
2
-
2
-1
-(
3
+4)
(2)
2a+2
a-1
÷(a+1)-
a
2
-1
a
2
-2a+1
.
(20口2·崇安区一模)(口)计算:
8
-(
口
2
)
-口
-
|2-2
2
|
(2)先化简,再求值:
x-口
x
÷(x-
口
x
),其中x=
3
-口.
(2012·昌平区一模)计算:
(
1
3
)
-1
-2cos30°+
12
+(1-π
)
0
.
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