试题

题目:
计算:
(1)-0.5-(-3
1
4
)+2.75-(+7
1
2

(2)2
1
4
×(-
6
7
)÷(
1
2
-2)

(3)-81÷
1
3
-
1
3
÷(-
1
9
)

(4)8×(-
3
4
)×(-4)×(-2)

(5)(1-1
1
2
-
3
8
+
7
12
)×(-24)
(6)3+50÷2×(-
1
5
)-1
(7)
7
12
÷(-
1
5
)+(-20)÷
12
7
-
7
12
÷(-
1
13
)

答案
解:(1)原式=-
1
2
+3
1
4
+2
3
4
-7
1
2

=-
1
2
+(-7
1
2
)+3
1
4
+2
3
4

=-8+6
=-2;
(2)原式=
9
4
×(-
6
7
)×(-
3
2

=
9
4
×
6
7
×
3
2

=
81
28

(3)原式=-81×3+
1
3
×9
=-243+3
=-240;
(4)原式=-(8×
3
4
×4×2)=-48;
(5)原式=1×(-24)-
3
2
×(-24)-
3
8
×(-24)+
7
12
×(-24)
=-24+36+9-14
=7;
(6)原式=30-50×
1
2
×
1
5
-1
=30-5-1
=24;
(7)原式=-
7
12
×5-20×
7
12
+13×
7
12

=(-5-20+13)×
7
12

=-12×
7
12

=-7.
解:(1)原式=-
1
2
+3
1
4
+2
3
4
-7
1
2

=-
1
2
+(-7
1
2
)+3
1
4
+2
3
4

=-8+6
=-2;
(2)原式=
9
4
×(-
6
7
)×(-
3
2

=
9
4
×
6
7
×
3
2

=
81
28

(3)原式=-81×3+
1
3
×9
=-243+3
=-240;
(4)原式=-(8×
3
4
×4×2)=-48;
(5)原式=1×(-24)-
3
2
×(-24)-
3
8
×(-24)+
7
12
×(-24)
=-24+36+9-14
=7;
(6)原式=30-50×
1
2
×
1
5
-1
=30-5-1
=24;
(7)原式=-
7
12
×5-20×
7
12
+13×
7
12

=(-5-20+13)×
7
12

=-12×
7
12

=-7.
考点梳理
有理数的混合运算.
(1)首先把小数统一化成分数,再把同分母的相加,这样计算起来方便.
(2)首先计算出括号里面的,再把乘除法统一成乘法后计算.
(3)首先计算除法,然后再计算加减法.
(4)首先确定符号,再把绝对值相乘即可.
(5)利用乘法分配律,用括号里的各项分别乘以(-24),后,再计算加减法.
(6)首先把除法化成乘法,再确定符号计算,最后计算加减法.
(7)首先计算除法,注意符号的确定,再提取公因式
7
12
,再计算加减括号里的法,最后乘以
7
12
即可.
此题主要考查了有理数的混合运算,关键是注意解题的方法,符号的确定.
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