试题

题目:
计算:
(1)3
1
2
-(-2
1
4
)+(-
1
3
)-
1
4
-(+
1
6
)

(2)(
1
2
-
3
4
-
7
8
)×(-8)

(3)-7×
5
4
+( -5 )×( -
5
4
 )-
2
5

(4)1+[1-(1-0.5×
1
3
)
]×[2-(-3)2].
答案
解:(1)原式=3
1
2
+2
1
4
-
1
3
-
1
4
-
1
6

=3
1
2
+(2
1
4
-
1
4
)-(
1
3
+
1
6

=3
1
2
+2-
1
2

=(3
1
2
-
1
2
)+2
=3+2
=5;    

(2)原式=
1
2
×(-8)-
3
4
×(-8)-
7
8
×(-8)
=-4+6+7
=9;     

(3)原式=
5
4
×[-7+5]-
2
5

=
5
4
×(-2)-
2
5

=-
5
2
-
2
5

=-
25
10
-
4
10

=-
29
10


(4)原式=1+[1-(1-
1
6
)]×[2-9]
=1+[1-
5
6
]×(-7)
=1+
1
6
×(-7)
=1-
7
6

=-
1
6

解:(1)原式=3
1
2
+2
1
4
-
1
3
-
1
4
-
1
6

=3
1
2
+(2
1
4
-
1
4
)-(
1
3
+
1
6

=3
1
2
+2-
1
2

=(3
1
2
-
1
2
)+2
=3+2
=5;    

(2)原式=
1
2
×(-8)-
3
4
×(-8)-
7
8
×(-8)
=-4+6+7
=9;     

(3)原式=
5
4
×[-7+5]-
2
5

=
5
4
×(-2)-
2
5

=-
5
2
-
2
5

=-
25
10
-
4
10

=-
29
10


(4)原式=1+[1-(1-
1
6
)]×[2-9]
=1+[1-
5
6
]×(-7)
=1+
1
6
×(-7)
=1-
7
6

=-
1
6
考点梳理
有理数的混合运算.
(1)先去括号,再根据加法结合律进行计算;
(2)根据乘法分配律进行计算;
(3)根据乘法结合律进行计算;
(4)先算括号里面的,再算乘除,最后算加减.
本题考查的是有理数的混合运算,在解答此类题目时要注意各种运算律的灵活应用.
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