如图:已知直线y=-
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| OA |
解:作以AB为直径的圆,圆心为Q,连接QO,作QD⊥X轴,QB⊥y轴,
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2
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| OA |
120π
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2
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解:作以AB为直径的圆,圆心为Q,连接QO,作QD⊥X轴,QB⊥y轴,
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2
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| OA |
120π
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2
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(2012·铁岭)如图所示,在平面直角坐标系中,直线OM是正比例函数y=-| 3 |
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为t(秒).
已知:如图,在平面直角坐标系中,A、B两点分别在x轴,y轴的正半轴上,点A(6,0),∠BAO=30°.