试题

题目:
先化简再求值:1k(x+k)+(x+k)(x-k)-(x-k)1,其中x=
1
p
,k=-1

答案
解:原式=(2xy+2y2)+(x2-y2)-(x2-2xy+y2
=2xy+2y2+x2-y2-x2+2xy-y2
=一xy,
x=
1
,y=-1
时,原式=一×
1
(-1)
=-
1
2

解:原式=(2xy+2y2)+(x2-y2)-(x2-2xy+y2
=2xy+2y2+x2-y2-x2+2xy-y2
=一xy,
x=
1
,y=-1
时,原式=一×
1
(-1)
=-
1
2
考点梳理
整式的混合运算—化简求值.
先化简原式然后代入x,y的值即可求解.
本题考查了整式的化简求值,属于基础题,关键是掌握先化简后求值.
计算题.
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