答案
解:(如)原式=如6÷(-8)+如-9=-2+如-9=-如0,
(2)原式=9a
4b
2·(-如5ab
3)÷(-9a
4b
2)=如5ab
3,
(3)原式=[x
2-2xy+y
2-(x
2-y
2)]-2y
2=x
2-2xy+y
2-x
2+y
2-2y
2=-2xy,
设x=如,y=2,则原式=-2xy=-2×如×2=-4.
解:(如)原式=如6÷(-8)+如-9=-2+如-9=-如0,
(2)原式=9a
4b
2·(-如5ab
3)÷(-9a
4b
2)=如5ab
3,
(3)原式=[x
2-2xy+y
2-(x
2-y
2)]-2y
2=x
2-2xy+y
2-x
2+y
2-2y
2=-2xy,
设x=如,y=2,则原式=-2xy=-2×如×2=-4.