试题

题目:
9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1),其中x=-
1
3
,y=2.
答案
解:9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1)
=9xy(x2+x-xy-y)-3y(3x2+2xy-3xy-2y2)+6y2(x2+x-xy-y)
=9x3y+9x2y-9x2y2-9xy2-9x2y+3xy2+6y3+6x2y2+6xy2-6xy3-6y3
=9x3y-3x2y2-6xy3
x=-
1
3
,y=2时,原式=9×(-
1
3
3×2-3×(-
1
3
2×22-6×(-
1
3
)×23
=-
2
3
-
4
3
+16
=14.
解:9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y2(x-y)(x+1)
=9xy(x2+x-xy-y)-3y(3x2+2xy-3xy-2y2)+6y2(x2+x-xy-y)
=9x3y+9x2y-9x2y2-9xy2-9x2y+3xy2+6y3+6x2y2+6xy2-6xy3-6y3
=9x3y-3x2y2-6xy3
x=-
1
3
,y=2时,原式=9×(-
1
3
3×2-3×(-
1
3
2×22-6×(-
1
3
)×23
=-
2
3
-
4
3
+16
=14.
考点梳理
整式的混合运算—化简求值.
先根据整式的乘法法则展开,再合并同类项,最后代入求出即可.
本题考查了整式的混合运算和求值的应用,主要考查学生的化简和计算能力.
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