答案
解:(1)∵b<a<0<c<2,
∴a+b<0,2-c>0,ac-1<0,
则原式=-2(a+b)-a(2-c)+2b-(ac-1)=-4a+1;
(2)原式=3m-6n+6+2m+3n-1=5m-3n+5;
(3)∵|x+
|+(y-2)
2=0,
∴x=-
,y=2,
则原式=4xy-x
2-5xy+y
2-x
2-3xy=y
2+2xy=4-1=3;
(4)A=2a
2+3ab-2a-1,B=-a
2+ab-1,
①3A+6B=3(2a
2+3ab-2a-1)+6(-a
2+ab-1)=6a
2+9ab-4a-3-6a
2+6ab-6=15ab-6a-9;
②根据题意得:15ab-6a=0,即15ab=6a,
解得:b=
.
解:(1)∵b<a<0<c<2,
∴a+b<0,2-c>0,ac-1<0,
则原式=-2(a+b)-a(2-c)+2b-(ac-1)=-4a+1;
(2)原式=3m-6n+6+2m+3n-1=5m-3n+5;
(3)∵|x+
|+(y-2)
2=0,
∴x=-
,y=2,
则原式=4xy-x
2-5xy+y
2-x
2-3xy=y
2+2xy=4-1=3;
(4)A=2a
2+3ab-2a-1,B=-a
2+ab-1,
①3A+6B=3(2a
2+3ab-2a-1)+6(-a
2+ab-1)=6a
2+9ab-4a-3-6a
2+6ab-6=15ab-6a-9;
②根据题意得:15ab-6a=0,即15ab=6a,
解得:b=
.