如图,正方形ABCD与正方形BEFG,且A、B、E在一直线上,已知AB=a,BE=b(b<a).| 1 |
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| x2+1 |
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| x2+1 |
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| n |
| 3(m+n) |
| 4ab |
| a-b+c | ||||||
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