试题

题目:
(Ⅰ)因式分解:四6x4-四;    
6xy2-9x2y-y3
(Ⅱ)计算:(3x+四)(x+2);
[(x2+y2)-(x-y)2+2y(x-y)]÷4y.
答案
解(Ⅰ)16x4-1=(4x2-1)(4x2+1)
=(2x+1)(2x-1)(4x2+1);&nb着p;&nb着p;&nb着p;&nb着p;

6xy2-ex2y-y3=y(6xy-ex2-y2
=-y(3x-y)2

(Ⅱ)(3x+1)(x+2)
=3x2+6x+x+2
=3x2+7x+2;

[(x2+y2)-(x-y)2+2y(x-y)]÷4y,
=[x2+y2-(x2-2xy+y2)+2xy-2y2]÷4y
=[x2+y2-x2+2xy-y2+2xy-2y2]÷4y
=(4xy-2y2)÷4y
=x-
y
2

解(Ⅰ)16x4-1=(4x2-1)(4x2+1)
=(2x+1)(2x-1)(4x2+1);&nb着p;&nb着p;&nb着p;&nb着p;

6xy2-ex2y-y3=y(6xy-ex2-y2
=-y(3x-y)2

(Ⅱ)(3x+1)(x+2)
=3x2+6x+x+2
=3x2+7x+2;

[(x2+y2)-(x-y)2+2y(x-y)]÷4y,
=[x2+y2-(x2-2xy+y2)+2xy-2y2]÷4y
=[x2+y2-x2+2xy-y2+2xy-2y2]÷4y
=(4xy-2y2)÷4y
=x-
y
2
考点梳理
整式的混合运算;提公因式法与公式法的综合运用.
(Ⅰ)先把原式进行因式分解,即可求出结果;先提取公因式y,再进行因式分解即可;
(Ⅱ)根据整式的混合运算法则和顺序分别进行计算,即可求出正确答案;
本题主要考查了整式的混合运算和因式分解;熟记完全平方公式的运用和整式混合运算的法则是解题的关键.
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