试题

题目:
计算:
(1)
20
×
5

(2)4
2
×(-3
8

(3)
6a3
×
3a
2
(a≥0)
(4)
3
×
27

(5)
2
3
12
×
3
×
1
2
20

(6)
m
6
·
96m
(m≥0)
(7)
5ab
·
45a3b
(a≥0,b≥0)
(8)
27
×
8

(9)
72
×
1
6

(10)
2xy3
·
4x2y
(x≥0,y≥0)
答案
解:(1)
20
×
5
=10;

(2)4
2
×(-3
8
)=-12×4=-48;

(3)
6a3
×
3a
2
(a≥0)=3a2

(4)
3
×
27
=9;

(5)
2
3
12
×
3
×
1
2
20

=
2
3
×
1
2
12×3×20

=
1
3
×6×2
5

=4
5


(6)
m
6
·
96m
(m≥0)
=
m
6
×96m

=4m;

(7)
5ab
·
45a3b
(a≥0,b≥0)
=
225a4b2

=15a2b;

(8)
27
×
8
=
9×3×2×4
=6
6


(9)
72
×
1
6
=
72×
1
6
=
12
=2
3


(10)
2xy3
·
4x2y
(x≥0,y≥0)=
8x3y4
=2xy2
2x

解:(1)
20
×
5
=10;

(2)4
2
×(-3
8
)=-12×4=-48;

(3)
6a3
×
3a
2
(a≥0)=3a2

(4)
3
×
27
=9;

(5)
2
3
12
×
3
×
1
2
20

=
2
3
×
1
2
12×3×20

=
1
3
×6×2
5

=4
5


(6)
m
6
·
96m
(m≥0)
=
m
6
×96m

=4m;

(7)
5ab
·
45a3b
(a≥0,b≥0)
=
225a4b2

=15a2b;

(8)
27
×
8
=
9×3×2×4
=6
6


(9)
72
×
1
6
=
72×
1
6
=
12
=2
3


(10)
2xy3
·
4x2y
(x≥0,y≥0)=
8x3y4
=2xy2
2x
考点梳理
二次根式的乘除法.
(1)根据二次根式的乘法运算直接得出即可;
(2)根据二次根式的乘法运算直接得出即可;
(3)根据二次根式的乘法运算进而化简得出即可;
(4)根据二次根式的乘法运算直接得出即可;
(5)根据二次根式的乘法运算直接得出即可;
(6)根据二次根式的乘法运算直接得出即可;
(7)根据二次根式的乘法运算进而化简得出即可;
(8)根据二次根式的乘法运算进而化简得出即可;
(9)根据二次根式的乘法运算进而化简得出即可;
(10)根据二次根式的乘法运算进而化简得出即可.
此题主要考查了二次根式的乘法运算,正确化简二次根式是解题关键.
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