答案
解:(1)水对杯底的压强:P=ρgh=1.0×10
3kg/m
3×10N/kg×0.1m=1000Pa;
(2)由F=ps得F=1000pa×0.01m
2=10N;
(3)烧杯对桌面的压强:P=
=
=1100Pa
答:杯底受到的水的压强为1000pa,杯底受到水的压力为10N,桌面受到盛水烧杯的压强为1100Pa.
解:(1)水对杯底的压强:P=ρgh=1.0×10
3kg/m
3×10N/kg×0.1m=1000Pa;
(2)由F=ps得F=1000pa×0.01m
2=10N;
(3)烧杯对桌面的压强:P=
=
=1100Pa
答:杯底受到的水的压强为1000pa,杯底受到水的压力为10N,桌面受到盛水烧杯的压强为1100Pa.