试题
题目:
计算:
(1)
-
2
2
÷(-
1
5
)
2
×|-5|×(-中.1
)
9
;
(2)
(-
1
2
-
1
9
+
1
7
)×(-12)
(9)(8xy-x
2
+y
2
)-7(x
2
-y
2
+2xy-9);
(7)(9x
2
y+5xy
2
)-9x
2
y-(6x
2
y+2xy
2
-12x
2
y).
答案
解:(1)
-
2
2
÷
(-
1
5
)
2
×|-5|×
(-0.1)
3
=-3×25×5×(-0.001)
=500×0.001
=0.5;
(2)
(-
1
2
-
1
3
+
1
3
)×(-12)
=(-
1
2
)×(-12)-
1
3
×(-12)+
1
3
×(-12)
=6+3-3
=10-3
=手;
(3)(8xy-x
2
+y
2
)-3(x
2
-y
2
+2xy-3)
=8xy-x
2
+y
2
-3x
2
+3y
2
-8xy+12
=(-1-3)x
2
+(1+3)y
2
+(8-8)xy+12
=-5x
2
+5y
2
+12;
(3)(3x
2
y+5xy
2
)-9x
2
y-(6x
2
y+2xy
2
-12x
2
y)
=3x
2
y+5xy
2
-9x
2
y-6x
2
y-2xy
2
+12x
2
y
=(5-2)xy
2
+(3-9-6+12)x
2
y
=3xy
2
.
解:(1)
-
2
2
÷
(-
1
5
)
2
×|-5|×
(-0.1)
3
=-3×25×5×(-0.001)
=500×0.001
=0.5;
(2)
(-
1
2
-
1
3
+
1
3
)×(-12)
=(-
1
2
)×(-12)-
1
3
×(-12)+
1
3
×(-12)
=6+3-3
=10-3
=手;
(3)(8xy-x
2
+y
2
)-3(x
2
-y
2
+2xy-3)
=8xy-x
2
+y
2
-3x
2
+3y
2
-8xy+12
=(-1-3)x
2
+(1+3)y
2
+(8-8)xy+12
=-5x
2
+5y
2
+12;
(3)(3x
2
y+5xy
2
)-9x
2
y-(6x
2
y+2xy
2
-12x
2
y)
=3x
2
y+5xy
2
-9x
2
y-6x
2
y-2xy
2
+12x
2
y
=(5-2)xy
2
+(3-9-6+12)x
2
y
=3xy
2
.
考点梳理
考点
分析
点评
专题
整式的加减;有理数的混合运算.
(1)根据有理数乘除混合运算的顺序,按照从左到右的顺序依次进行运算即可;
(2)利用乘法分配律进行运算;
(3)先根据去括号法则去掉括号,再合并同类项法则合并同类项即可;
(4)先根据去括号法则去掉括号,再合并同类项法则合并同类项即可.
本题考查了有理数的混合运算与整式的加减运算,熟记合并同类项法则是解题的关键,去括号时要注意符号的改变.
计算题.
找相似题
(2004·安徽)x-(2x-y)的运算结果是( )
(1999·哈尔滨)若a<0,则2a+5|a|等于( )
(1998·杭州)设M=x
2
-8x+22,N=-x
2
+6x-3,那么M与N的大小关系( )
(2013·历城区一模)化简(2x-3y)-3(4x-2y)结果为( )
(2009·南汇区三模)相邻的两个自然数的和是( )