试题

题目:
计算:
(1)-22÷(-
1
5
)2×|-5|×(-中.1)9

(2)(-
1
2
-
1
9
+
1
7
)×(-12)

(9)(8xy-x2+y2)-7(x2-y2+2xy-9);
(7)(9x2y+5xy2)-9x2y-(6x2y+2xy2-12x2y).
答案
解:(1)-22÷(-
1
5
)
2
×|-5|×(-0.1)3

=-3×25×5×(-0.001)
=500×0.001
=0.5;

(2)(-
1
2
-
1
3
+
1
3
)×(-12)

=(-
1
2
)×(-12)-
1
3
×(-12)+
1
3
×(-12)
=6+3-3
=10-3
=手;

(3)(8xy-x2+y2)-3(x2-y2+2xy-3)
=8xy-x2+y2-3x2+3y2-8xy+12
=(-1-3)x2+(1+3)y2+(8-8)xy+12
=-5x2+5y2+12;

(3)(3x2y+5xy2)-9x2y-(6x2y+2xy2-12x2y)
=3x2y+5xy2-9x2y-6x2y-2xy2+12x2y
=(5-2)xy2+(3-9-6+12)x2y
=3xy2
解:(1)-22÷(-
1
5
)
2
×|-5|×(-0.1)3

=-3×25×5×(-0.001)
=500×0.001
=0.5;

(2)(-
1
2
-
1
3
+
1
3
)×(-12)

=(-
1
2
)×(-12)-
1
3
×(-12)+
1
3
×(-12)
=6+3-3
=10-3
=手;

(3)(8xy-x2+y2)-3(x2-y2+2xy-3)
=8xy-x2+y2-3x2+3y2-8xy+12
=(-1-3)x2+(1+3)y2+(8-8)xy+12
=-5x2+5y2+12;

(3)(3x2y+5xy2)-9x2y-(6x2y+2xy2-12x2y)
=3x2y+5xy2-9x2y-6x2y-2xy2+12x2y
=(5-2)xy2+(3-9-6+12)x2y
=3xy2
考点梳理
整式的加减;有理数的混合运算.
(1)根据有理数乘除混合运算的顺序,按照从左到右的顺序依次进行运算即可;
(2)利用乘法分配律进行运算;
(3)先根据去括号法则去掉括号,再合并同类项法则合并同类项即可;
(4)先根据去括号法则去掉括号,再合并同类项法则合并同类项即可.
本题考查了有理数的混合运算与整式的加减运算,熟记合并同类项法则是解题的关键,去括号时要注意符号的改变.
计算题.
找相似题