试题

题目:
计算或化简
(1)23-17-(-7)+(-16)
(2)-14-(1-0.5)×
1
3
×[2-(-3)2]

(3)a2-2a-4a2+a
(4)(3a2b-ab2)-4(-ab2+3a2b)
答案
解:(1)原式=23-17+7-16
=-3;
        
(2)原式=-1-0.5×
1
3
×(2-9)
=-1-
1
6
×(-7)
=-1+
7
6

=
1
6


(3)原式=(1-4)a2-(2-1)a
=-3a2-a;

(4)原式=3a2b-ab2+4ab2-12a2b
=(3-12)a2b-(1-4)ab2
=-9a2b+3ab2
解:(1)原式=23-17+7-16
=-3;
        
(2)原式=-1-0.5×
1
3
×(2-9)
=-1-
1
6
×(-7)
=-1+
7
6

=
1
6


(3)原式=(1-4)a2-(2-1)a
=-3a2-a;

(4)原式=3a2b-ab2+4ab2-12a2b
=(3-12)a2b-(1-4)ab2
=-9a2b+3ab2
考点梳理
整式的加减;有理数的混合运算.
(1)先去括号,再从左到右依次计算即可;
(2)先算括号里面的,再算乘方,乘法,最后算加减;
(3)直接合并同类项即可;
(4)先去括号,再合并同类项即可.
本题考查的是整式的加减,熟知整式的加减实质上就是合并同类项是解答此题的关键.
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