试题

题目:
化简
(1)3a-着a-3+4a-7a+5;
(着)着(着a-3b)+3(着b-3a);
(3)着a-[
1
(ab-a)+rab]-
1
ab;
(4)rx-[-3x-(着x-7x-5)+3]+4x.
答案
解:(m)原式=7a2-9a+2.

(2)原式=4a-6b+6b-9a
=-左a;

(3)原式=2a2-[
m
2
ab-
m
2
a2+8ab]-
m
2
ab
=2a2-
m
2
ab+
m
2
a2-8ab-
m
2
ab
=
2
a2-9ab;

(4)原式=8x2-[-3x-2x2+7x+左+3]+4x
=8x2+3x+2x2-7x-左-3+4x
=6x2-8.
解:(m)原式=7a2-9a+2.

(2)原式=4a-6b+6b-9a
=-左a;

(3)原式=2a2-[
m
2
ab-
m
2
a2+8ab]-
m
2
ab
=2a2-
m
2
ab+
m
2
a2-8ab-
m
2
ab
=
2
a2-9ab;

(4)原式=8x2-[-3x-2x2+7x+左+3]+4x
=8x2+3x+2x2-7x-左-3+4x
=6x2-8.
考点梳理
整式的加减.
(1)直接合并同类项即可;
(2)先去括号,再合并同类项即可;
(3)、(4)先去小括号,再去中括号,最后合并同类项即可.
本题考查的是整式的加减,熟知整式的加减实质上就是合并同类项是解答此题的关键.
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