答案
解:∵菱形ABCD的对角线AC、BD交于点O,且AC=16cm,BD=12cm,
∴AO=CO=8cm,DO=BO=6cm,∠AOB=90°,
∴在Rt△AOB中
AB=
=10(cm),
菱形面积为:
AC×BD=DH×AB,
则
×16×12=10×DH,
解得:DH=
(cm),
答:菱形ABCD的高DH为
cm,AB的长为10cm.
解:∵菱形ABCD的对角线AC、BD交于点O,且AC=16cm,BD=12cm,
∴AO=CO=8cm,DO=BO=6cm,∠AOB=90°,
∴在Rt△AOB中
AB=
=10(cm),
菱形面积为:
AC×BD=DH×AB,
则
×16×12=10×DH,
解得:DH=
(cm),
答:菱形ABCD的高DH为
cm,AB的长为10cm.