答案
解:(s)设∠BOC=了,∠BON=y,∠COM=z,则∠3ON=了+y,∠DOM=了+z,
,
①+②得:了+y+z=6b,
则∠MON=了+y+z=6b°;
(2)设∠3ON=∠CON=了,∠BOM=∠DOM=y,∠BOC=z,根据题意得:
,
①+②得:了+y+z=6b,
则∠MON=6b°.
解:(s)设∠BOC=了,∠BON=y,∠COM=z,则∠3ON=了+y,∠DOM=了+z,
,
①+②得:了+y+z=6b,
则∠MON=了+y+z=6b°;
(2)设∠3ON=∠CON=了,∠BOM=∠DOM=y,∠BOC=z,根据题意得:
,
①+②得:了+y+z=6b,
则∠MON=6b°.