答案
解:
(1)h=20cm=0.2m,从图可知,拉力F=1.2N,n=3,则S=3h=3×0.2m=0.6m,
拉力做的总功为:
W
总=FS=1.2N×0.6m=0.72J,
拉力做功的功率为:P=
=
=0.36W.
答:拉力的功率为0.36W.
(2)对物体做的有用功为:
W
有用=Gh=3.0N×0.2m=0.6J,
该滑轮组的机械效率为:
η=
×100%=
×100%≈83.3%.
答:滑轮组的机械效率为83.3%.
解:
(1)h=20cm=0.2m,从图可知,拉力F=1.2N,n=3,则S=3h=3×0.2m=0.6m,
拉力做的总功为:
W
总=FS=1.2N×0.6m=0.72J,
拉力做功的功率为:P=
=
=0.36W.
答:拉力的功率为0.36W.
(2)对物体做的有用功为:
W
有用=Gh=3.0N×0.2m=0.6J,
该滑轮组的机械效率为:
η=
×100%=
×100%≈83.3%.
答:滑轮组的机械效率为83.3%.