答案
已知:L=200m,v=15m/s,t=2min=1200s
求:s,L′
解:(1)∵v=
,
∴s=vt=15m/s×120s=1800m;
(2)L′=s-L=1800m-200m=1600m.
答:(1)这段时间火车行驶的路程为1800m;
(2)大桥的长度为1600m.
已知:L=200m,v=15m/s,t=2min=1200s
求:s,L′
解:(1)∵v=
,
∴s=vt=15m/s×120s=1800m;
(2)L′=s-L=1800m-200m=1600m.
答:(1)这段时间火车行驶的路程为1800m;
(2)大桥的长度为1600m.