题目：
（2013·滨湖区一模）计算：（1）|-
| 2 |
| 4 |
| 1 |
| 3 |
（2）化简
| a2 |
| a+1 |
答案
解：（1）原式=| 2 |
| ||
| 2 |
=1；
（2）原式=
| a2 |
| a+1 |
| (a+1)(a-1) |
| a+1 |
=
| a2-(a2-1) |
| a+1 |
=
| 1 |
| a+1 |
解：（1）原式=
| 2 |
| ||
| 2 |
=1；
（2）原式=
| a2 |
| a+1 |
| (a+1)(a-1) |
| a+1 |
=
| a2-(a2-1) |
| a+1 |
=
| 1 |
| a+1 |
| 2 |
| 4 |
| 1 |
| 3 |
| a2 |
| a+1 |
| 2 |
| ||
| 2 |
| a2 |
| a+1 |
| (a+1)(a-1) |
| a+1 |
| a2-(a2-1) |
| a+1 |
| 1 |
| a+1 |
| 2 |
| ||
| 2 |
| a2 |
| a+1 |
| (a+1)(a-1) |
| a+1 |
| a2-(a2-1) |
| a+1 |
| 1 |
| a+1 |
（2009·三明）如图，△ABC是边长为2的等边三角形，将△ABC沿射线BC向右平移得到△DCE，连接AD、BD，下列结论错误的是（ ）