试题

题目:
先化简,再求值
(9)362y-[26y2-2(6y-
3
2
62y)+6y]+36y2
,其中6=3,y=-
9
3

(2)已知a+b=-2,ab=3,求2[ab+(-3a)]-3(2b-ab)的值.
答案
解:(1)原式=3x2y-[2xy2-2xy+3x2y+xy]+3xy2
=3x2y-2xy2+2xy-3x2y-xy+3xy2
=xy+xy2
把x=3,y=-
1
3
代入得:原式=-1+
1
3
=-
2
3


(2)∵a+b=-2,ab=3,
∴原式=2[ab-3a]-6b+3ab
=2ab-6a-6b+3ab
=5ab-6(a+b)
=5×3-6×(-2)
=27.
解:(1)原式=3x2y-[2xy2-2xy+3x2y+xy]+3xy2
=3x2y-2xy2+2xy-3x2y-xy+3xy2
=xy+xy2
把x=3,y=-
1
3
代入得:原式=-1+
1
3
=-
2
3


(2)∵a+b=-2,ab=3,
∴原式=2[ab-3a]-6b+3ab
=2ab-6a-6b+3ab
=5ab-6(a+b)
=5×3-6×(-2)
=27.
考点梳理
整式的加减—化简求值.
(1)去括号后合并同类项即可,注意先去小括号,再去中括号.
(2)去括号后合并同类项,把a+b和ab当作一个整体代入求出即可.
本题考查了整式的加减法则的应用,关键是正确去括号和合并同类项,注意整体思想的灵活运用.
计算题.
找相似题