试题

题目:
(1)(-12)÷4×(-6)÷2
(2)-1+5÷(-
1
4
)×(-4)
(3)-12008-(0.5-
2
3
)÷
1
3
×[-2×(-3)2]
(4)-24-(1-0.5)×
1
3
×[22-(-3)2].
答案
解:(1)原式=-3×(-6)÷2
=18÷2
=9;

(2)原式=-1+5×(-4)×(-4)
=-1-20×(-4)
=-1+80
=79;

(3)原式=-1-(-
1
6
)×3×[-2×9]
=-1+
1
2
×3×(-18)
=-1+
3
2
×(-18)
=-1-27
=-28;

(4)原式=-24-0.5×
1
3
×[4-9]
=-24-0.5×
1
3
×(-5)
=-16-
1
6
×(-5)
=-16+
5
6

=-
91
6

解:(1)原式=-3×(-6)÷2
=18÷2
=9;

(2)原式=-1+5×(-4)×(-4)
=-1-20×(-4)
=-1+80
=79;

(3)原式=-1-(-
1
6
)×3×[-2×9]
=-1+
1
2
×3×(-18)
=-1+
3
2
×(-18)
=-1-27
=-28;

(4)原式=-24-0.5×
1
3
×[4-9]
=-24-0.5×
1
3
×(-5)
=-16-
1
6
×(-5)
=-16+
5
6

=-
91
6
考点梳理
有理数的混合运算.
(1)按照从左到右的运算顺序依次计算即可;
(2)先算乘除,再算加减即可;
(3)(4)先算括号里面的,再算乘方,乘除,最后算加减即可.
本题考查的是有理数的混合运算,熟知有理数混合运算的法则是解答此题的关键.
计算题.
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