试题

题目:
计算:
①-40-一8-(-19)+(-一4);
②-0.5-(-3
1
4
)+一.75-(+7
1
);
③(-5)×8×(-7)×(-0.一5);
(
1
-
3
+
5
4
-
5
6
-
3
8
)×(-一4)

[1-(1-0.5×
1
3
)]×[一-(-3)]

答案
解:(三)原式=-20-28+三9-22=-68+三9-22=-73;
(2)原式=-0.k+3.2k+2.7k-7.k=-8+6=-2;
(3)原式=-20×(-7)×(-
2
)=-70;
(2)原式=-三2+三6-30+20+9=3;
(k)原式=[三-(三-
6
)]×(2-9)
=(三-
k
6
)×(-7)
=-
7
6

解:(三)原式=-20-28+三9-22=-68+三9-22=-73;
(2)原式=-0.k+3.2k+2.7k-7.k=-8+6=-2;
(3)原式=-20×(-7)×(-
2
)=-70;
(2)原式=-三2+三6-30+20+9=3;
(k)原式=[三-(三-
6
)]×(2-9)
=(三-
k
6
)×(-7)
=-
7
6
考点梳理
有理数的混合运算.
(1)、(2)先去括号,再计算加减;
(3)从左到右的顺序计算;
(4)乘法分配律的利用;
(5)先算括号,最后算乘法.
有理数的混合运算,要根据题目,灵活选取方法;一般都是先乘方,后乘除,最后计算加减.
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