试题

题目:
计算
(1)(2a22
(2)(a2b)3
(3)(-3a)3(a24
(4)(a23+5a3·a3-(2a23
(5)0.1255×85
(6)0.252007×42009
(7)2(y32·y3-(3y32+(5y)2·y7
答案
解:(1)(2a22=4a4
(2)(a2b)3=a6b3
(3)(-3a)3(a24=-27a3·a8=-27a11
(4)(a23+5a3·a3-(2a23=a6+5a6-8a6=-2a6
(5)0.1255×85=(0.125×8)5=15=1;
(6)0.252007×42009=0.252007×·42007×42=(0.25×4)2007×16=1×16=16;
(7)2(y32·y3-(3y32+(5y)2·y7=2y6·y3-9(y32+25y2·y7=2y9-9y6+25y9=27y9-9y6
解:(1)(2a22=4a4
(2)(a2b)3=a6b3
(3)(-3a)3(a24=-27a3·a8=-27a11
(4)(a23+5a3·a3-(2a23=a6+5a6-8a6=-2a6
(5)0.1255×85=(0.125×8)5=15=1;
(6)0.252007×42009=0.252007×·42007×42=(0.25×4)2007×16=1×16=16;
(7)2(y32·y3-(3y32+(5y)2·y7=2y6·y3-9(y32+25y2·y7=2y9-9y6+25y9=27y9-9y6
考点梳理
整式的混合运算;有理数的混合运算.
(1)(2)(3)按幂的乘方、同底数幂的运算法则计算;
(4)(7)先按幂的乘方、同底数幂的运算法则计算,再合并同类项;
(5)用积的乘方的逆运算计算;
(6)用积的乘方、同底数幂的逆运算计算.
此题考查幂的运算在整式运算和有理数运算中的应用,掌握法则的同时,要灵活应用.
计算题.
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