答案
解:(1)把这组数据从小到大排列为0.01,0.01,0.02,0.03,0.03,0.03,0.03,0.03,0.04,0.04,0.04,0.05,
故中位数是0.03(g/m
3).
出现次数最多的数据是0.03g/m
3,所以众数是0.03g/m
3.
(2)∵平均数=(0.01+0.01+0.02+0.03+0.03+0.03+0.03+0.03+0.04+0.04+0.04+0.05)÷12=0.03 (g/m
3),
∵0.03 g/m
3>0.025 g/m
3
∴这天该城市的空气不符合要求.
解:(1)把这组数据从小到大排列为0.01,0.01,0.02,0.03,0.03,0.03,0.03,0.03,0.04,0.04,0.04,0.05,
故中位数是0.03(g/m
3).
出现次数最多的数据是0.03g/m
3,所以众数是0.03g/m
3.
(2)∵平均数=(0.01+0.01+0.02+0.03+0.03+0.03+0.03+0.03+0.04+0.04+0.04+0.05)÷12=0.03 (g/m
3),
∵0.03 g/m
3>0.025 g/m
3
∴这天该城市的空气不符合要求.