试题

题目:
计算:
(1)-14-
1
6
×[2-(-3)2];
(2)(-1)4-(1-0.5)×
1
3
×[2-(-2)2];
(3)(-2)2-22-|-
1
4
|×(-1)2
(4)(-2
1
2
)×(-0.5)3×(-2)2×(-8).
答案
解:(1)-14-
1
6
×[2-(-3)2],
=-1-
1
6
×(2-9),
=-1+
7
6

=
1
6


(2)(-1)4-(1-0.5)×
1
3
×[2-(-2)2],
=1-
1
2
×
1
3
×(2-4),
=1+
1
3

=
4
3


(3)(-2)2-22-|-
1
4
|×(-1)2
=4-4-
1
4
×1,
=-
1
4


(4)(-2
1
2
)×(-0.5)3×(-2)2×(-8),
=-
5
2
×(-
1
8
)×4×(-8),
=-
5
2
×
1
8
×4×8,
=-10.
解:(1)-14-
1
6
×[2-(-3)2],
=-1-
1
6
×(2-9),
=-1+
7
6

=
1
6


(2)(-1)4-(1-0.5)×
1
3
×[2-(-2)2],
=1-
1
2
×
1
3
×(2-4),
=1+
1
3

=
4
3


(3)(-2)2-22-|-
1
4
|×(-1)2
=4-4-
1
4
×1,
=-
1
4


(4)(-2
1
2
)×(-0.5)3×(-2)2×(-8),
=-
5
2
×(-
1
8
)×4×(-8),
=-
5
2
×
1
8
×4×8,
=-10.
考点梳理
有理数的乘方.
分别根据有理数的混合运算顺序,先算乘方,再算乘除,最后算加减,有括号先算括号里面的进行计算即可得解.
本题考查了有理数的乘方,有理数的混合运算,要注意-14和(-1)4的区别.
计算题.
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