题目：
阅读下列第（1）题中的计算方法，再计算第（2）题中式子的值．（1）-5
| 5 |
| 6 |
| 2 |
| 3 |
| 3 |
| 4 |
| 1 |
| 2 |
解：原式=[（-5）+（-
| 5 |
| 6 |
| 2 |
| 3 |
| 3 |
| 4 |
| 1 |
| 2 |
=[（-5）+（-9）+（+17）+（-3）]+[（-
| 5 |
| 6 |
| 2 |
| 3 |
| 3 |
| 4 |
| 1 |
| 2 |
=0+（-1
| 1 |
| 4 |
=-1
| 1 |
| 4 |
上面这种方法叫拆项法．仿照上述方法计算：
（2）（-2008
| 5 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
答案
解：原式=（-2008）+（-| 5 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
=（-2008-2007+4017-1）+（-
| 5 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
=1-
| 4 |
| 3 |
=-
| 1 |
| 3 |
解：原式=（-2008）+（-
| 5 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
=（-2008-2007+4017-1）+（-
| 5 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
=1-
| 4 |
| 3 |
=-
| 1 |
| 3 |
