试题

题目:
①(
3
8
+
1
6
-
3
4
)×(-24)
②-22+3×(-1)4-(-4)×5
③3a2+5-2a2-2a+3a-8
④3(-ab+2a)-2(3a-b)
答案
解:①(
3
8
+
1
6
-
3
4
)×(-24),
=
3
8
×
(-24)+
1
6
×
(-24)-
3
4
×
(-24),
=-9-4+18,
=5;

②-22+3×(-1)4-(-4)×5,
=-4+3+20,
=19;

③3a2+5-2a2-2a+3a-8,
=a2+a-3;

④3(-ab+2a)-2(3a-b),
=-3ab+6ab-6a+2b,
=3ab-6a+2b.
解:①(
3
8
+
1
6
-
3
4
)×(-24),
=
3
8
×
(-24)+
1
6
×
(-24)-
3
4
×
(-24),
=-9-4+18,
=5;

②-22+3×(-1)4-(-4)×5,
=-4+3+20,
=19;

③3a2+5-2a2-2a+3a-8,
=a2+a-3;

④3(-ab+2a)-2(3a-b),
=-3ab+6ab-6a+2b,
=3ab-6a+2b.
考点梳理
整式的加减;有理数的混合运算.
运用有理数的运算法则,以及乘方运算,去括号,进行合并同类项,可以得出结果.
此题主要考查了有理数的运算,以及乘法的分配律和整式的加减运算,题目比较典型.
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