试题

题目:
计算.
(1)3(x2-2xy)-2(-3xy+y2);
(2)(a3-2a2+a+7)-3a2+
1
4
a-(2x2-7a)

(3)(6m2n-5mn2)-6(
1
3
m2n-
1
2
mn2)

答案
解:(1)原式=3x2-6xy+6xy-2y2
=3x2-2y2

(2)原式=a3-2a2+a+7-3a2+
1
4
a-2x2+7a
=a3-5a2+
33a
4
+7-2x2
=a3-5a2+
33a
4
-2x2+7;

(3)原式=6m2n-5mn2-2m2n+3mn2
=4m2n-2mn2
解:(1)原式=3x2-6xy+6xy-2y2
=3x2-2y2

(2)原式=a3-2a2+a+7-3a2+
1
4
a-2x2+7a
=a3-5a2+
33a
4
+7-2x2
=a3-5a2+
33a
4
-2x2+7;

(3)原式=6m2n-5mn2-2m2n+3mn2
=4m2n-2mn2
考点梳理
整式的加减.
(1)、(2)、(3)先去括号,再合并同类项即可.
本题考查了整式的加减,熟悉合并同类项法则是解题的关键.
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