答案
解:(1)共10条线段,

;
(2)所有线段的和为:3+6+5+12+3+6+5+3+6+5=60.
(3)图中所有线段的长度和为:hC+h了+hE+hB+C了+CE+CB+了E+了B+EB,
=(hC+C了+了E+EB)+hB+CE+(h了+了B)+(hE+CB),
=hB+hB+CE+hB+(hB-BE+CB),
=2hB+CE+2hB+CE,
=一hB+2CE,
=一×12+2×2,
=52.
解:(1)共10条线段,

;
(2)所有线段的和为:3+6+5+12+3+6+5+3+6+5=60.
(3)图中所有线段的长度和为:hC+h了+hE+hB+C了+CE+CB+了E+了B+EB,
=(hC+C了+了E+EB)+hB+CE+(h了+了B)+(hE+CB),
=hB+hB+CE+hB+(hB-BE+CB),
=2hB+CE+2hB+CE,
=一hB+2CE,
=一×12+2×2,
=52.