试题

题目:
(1+
1
2
)(1-
1
2
)(1+
1
22
)(1+
1
24
)(1+
1
28
)(1+
1
216
)

答案
解:原式=(1-
1
22
)(1+
1
22
)(1+
1
24
)(1+
1
28
)(1+
1
216

=(1-
1
24
)(1+
1
24
)(1+
1
28
)(1+
1
216

=(1-
1
28
)(1+
1
28
)(1+
1
216

=(1-
1
216
)(1+
1
216

=1-
1
232

解:原式=(1-
1
22
)(1+
1
22
)(1+
1
24
)(1+
1
28
)(1+
1
216

=(1-
1
24
)(1+
1
24
)(1+
1
28
)(1+
1
216

=(1-
1
28
)(1+
1
28
)(1+
1
216

=(1-
1
216
)(1+
1
216

=1-
1
232
考点梳理
平方差公式.
由平方差公式,(1+
1
2
)(1-
1
2
)=1-
1
22
,(1-
1
22
)(1+
1
22
)=1-
1
24
,依此类推,从而得出结果.
本题考查了平方差公式的反复应用,是基础知识要熟练掌握.
计算题.
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