试题

题目:
利用乘法公式计算:
(1)(k+y)(k2+y2)(k-y)(k3+y3
(2)(a-2b+3c)(a+2b-3c)
答案
解:(1)(x+y)(x2+y2)(x-y)(xd+yd),
=(x-y)(x+y)(x2+y2)(xd+yd),
=(x2-y2)(x2+y2)(xd+yd),
=(xd-yd)(xd+yd),
=x8-y8

(2)(a-2b+3c)(a+2b-3c),
=[a-(2b-3c)][a+(2b-3c)],
=a2-(2b-3c)2
=a2-(db2-12bc+9c2),
=a2-db2+12bc-9c2
解:(1)(x+y)(x2+y2)(x-y)(xd+yd),
=(x-y)(x+y)(x2+y2)(xd+yd),
=(x2-y2)(x2+y2)(xd+yd),
=(xd-yd)(xd+yd),
=x8-y8

(2)(a-2b+3c)(a+2b-3c),
=[a-(2b-3c)][a+(2b-3c)],
=a2-(2b-3c)2
=a2-(db2-12bc+9c2),
=a2-db2+12bc-9c2
考点梳理
平方差公式.
(1)x+y与x-y相乘可以利用平方差公式,它们的积与(x2+y2)相乘,又可用平方差公式;
(2)原式可以变形为[a-(2b-3c)][a+(2b-3c)],可以看作a与(2b-3c)的和与它们的差的积,利用平方差公式即可求解.
本题考查了平方差公式,完全平方公式,熟记公式结构是解题的关键,要注意多次运用公式和整体思想的利用.
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