答案
解:
(1)∵G=540N,h=0.05m,
∴晓东同学每次跳离地面做的功为:W=Gh=540N×0.05m=27J.
(2)∵t=1min=60s跳绳200次,
∴1min内做的功为:W
总=200×W=200×27J=5400J,
跳绳功率为:P=
=
=90W.
答:(1)晓东同学每次跳离地面做的功是27J.
(2)他在这1min的跳绳中功率是90W.
解:
(1)∵G=540N,h=0.05m,
∴晓东同学每次跳离地面做的功为:W=Gh=540N×0.05m=27J.
(2)∵t=1min=60s跳绳200次,
∴1min内做的功为:W
总=200×W=200×27J=5400J,
跳绳功率为:P=
=
=90W.
答:(1)晓东同学每次跳离地面做的功是27J.
(2)他在这1min的跳绳中功率是90W.