答案
解:(1)木块受重力G=mg=0.75kg×10N/kg=7.5N;
(2)木块密度ρ=
=
=0.75×10
3kg/m
3;
(3)木块匀速移动受到的摩擦力f=3F=3×0.5N=1.5N.
答:(1)木块受到的重力为7.5;
(2)木块的密度为0.75×10
3kg/m
3;
(3)木块匀速移动受到的摩擦力为1.5N.
解:(1)木块受重力G=mg=0.75kg×10N/kg=7.5N;
(2)木块密度ρ=
=
=0.75×10
3kg/m
3;
(3)木块匀速移动受到的摩擦力f=3F=3×0.5N=1.5N.
答:(1)木块受到的重力为7.5;
(2)木块的密度为0.75×10
3kg/m
3;
(3)木块匀速移动受到的摩擦力为1.5N.