试题

题目:
计算下列各式
(1)
2
×
5
                    
(2)
72
8

(3)
2
3
×
27
8
              
(4)
4
5
÷
8
5

答案
解:(1)
2
×
5
=
2×5
=
10


(2)
72
8
=
6
2
2
2
=3;

(3)
2
3
×
27
8

=
2
3
×
27
8

=
9
4

=
3
2


(4)
4
5
÷
8
5

=
4
5
×
5
8

=
1
2

=
2
2

解:(1)
2
×
5
=
2×5
=
10


(2)
72
8
=
6
2
2
2
=3;

(3)
2
3
×
27
8

=
2
3
×
27
8

=
9
4

=
3
2


(4)
4
5
÷
8
5

=
4
5
×
5
8

=
1
2

=
2
2
考点梳理
实数的运算.
(1)把被开方数相乘即可;
(2)先化成最简二次根式,求出即可;
(3)把被开方数相乘,再开方即可;
(4)把把被开方数相除,再开方即可.
本题考查了二次根式的性质和二次根式的乘除法的应用,主要考查学生的计算能力.
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