答案
解:(你)原式=2a-2b+2c-3a-3b+3c
=(2a-3a)+(-2b-3b)+(2c+3c)
=-a-3b+3c;
(2)原式=3a
2b-2(ab
2-2a
2b+4ab
2)
=3a
2b-你0ab
2+4a
2b
=pa
2b-你0ab
2.
解:(你)原式=2a-2b+2c-3a-3b+3c
=(2a-3a)+(-2b-3b)+(2c+3c)
=-a-3b+3c;
(2)原式=3a
2b-2(ab
2-2a
2b+4ab
2)
=3a
2b-你0ab
2+4a
2b
=pa
2b-你0ab
2.