The coordinates of the three points A.B.C on the plane are (-5,-5),(-2,-1)and(-1,-2)respectively,the triangle ABC is( ) (英汉小词典:right直角的;isosceles等腰的;equilateral等边的;obtuse钝角的)
答案
B 解:如图过B作Y轴的平行线,过A作X轴的平行线,两线交于H,由勾股定理得:AB2=[(-2)-(-5)]2+[(-1)-(-5)]2, 即:AB2=25 同理:AC2=[(-1)-(-5)]2+[(-2)-(-5)]2,即:AC2=25, BC2=[(-1)-(-2)]2+[(-1)-(-2)]2,BC2=2, ∴AB=AC. 故选B.